2x(x-4)=2(x^2-6x-8)

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Solution for 2x(x-4)=2(x^2-6x-8) equation:


Simplifying
2x(x + -4) = 2(x2 + -6x + -8)

Reorder the terms:
2x(-4 + x) = 2(x2 + -6x + -8)
(-4 * 2x + x * 2x) = 2(x2 + -6x + -8)
(-8x + 2x2) = 2(x2 + -6x + -8)

Reorder the terms:
-8x + 2x2 = 2(-8 + -6x + x2)
-8x + 2x2 = (-8 * 2 + -6x * 2 + x2 * 2)
-8x + 2x2 = (-16 + -12x + 2x2)

Add '-2x2' to each side of the equation.
-8x + 2x2 + -2x2 = -16 + -12x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-8x + 0 = -16 + -12x + 2x2 + -2x2
-8x = -16 + -12x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-8x = -16 + -12x + 0
-8x = -16 + -12x

Solving
-8x = -16 + -12x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12x' to each side of the equation.
-8x + 12x = -16 + -12x + 12x

Combine like terms: -8x + 12x = 4x
4x = -16 + -12x + 12x

Combine like terms: -12x + 12x = 0
4x = -16 + 0
4x = -16

Divide each side by '4'.
x = -4

Simplifying
x = -4

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